How do you solve #abs[6x+7/5]<=6#?
See a solution process below:
We must solve the term within the absolute value function for both its negative and positive equivalent because the absolute value function takes any term, whether positive or negative, and converts it to its positive form.
Or
Instead, using interval notation:
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To solve the inequality (6x + \frac{7}{5} \leq 6), you need to consider two cases:

(6x + \frac{7}{5} \geq 0): In this case, the absolute value (6x + \frac{7}{5}) is equal to (6x + \frac{7}{5}). So, you can directly solve the inequality (6x + \frac{7}{5} \leq 6).

(6x + \frac{7}{5} < 0): In this case, the absolute value (6x + \frac{7}{5}) is equal to ((6x + \frac{7}{5})). So, you need to solve the inequality ((6x + \frac{7}{5}) \leq 6).
After solving both inequalities, you will get the solutions for (x).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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