How do you solve #abs(6 - 5y )>2#?

Answer 1

The solution is #y in ( -oo, 4/5)uu(8/5,+oo)#

There are #2# solutions for absolute values.
#|6-5y|>2#
#6-5y>2# and #-6+5y>2#
#5y<4# and #5y>8#
#y<4/5# and #y>8/5#

The solutions are

#S_1=y in( -oo, 4/5)#
#S_2=y in (8/5,+oo)#

Therefore,

#S=S_1uuS_2#
#=y in ( -oo, 4/5)uu(8/5,+oo)#

graph{(y-|6-5x|)(y-2)=0 [-5.55, 6.934, -0.245, 5.995]}

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Answer 2

#(-oo,4/5)uu(8/5,+oo)#

#"inequalities of the form "|x|>a#
#"always have solutions of the form"#
#x< -a" or "x > a#
#"thus we have to solve 2 inequalities"#
#6-5y < -2" or "6-5y>2#
#color(blue)"first solution"#
#6-5y < -2larr"subtract 6 from both sides"#
#rArr-5y < -8larr"divide both sides by "-5#
#rArry>8/5larrcolor(blue)"reverse direction of sign"#
#color(blue)"second solution"#
#6-5y>2larr"subtract 6 from both sides"#
#rArr-5y> -4larr"divide both sides by " -5#
#y< 4/5larrcolor(blue)"reverse direction of sign"#
#"combining the solutions gives"#
#(-oo,4/5)uu(8/5,+oo)#
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Answer 3

To solve the absolute value inequality (|6 - 5y| > 2), set up two cases: one where (6 - 5y) is greater than 2, and another where (6 - 5y) is less than -2. Solve each case separately to find the solution set for (y).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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