How do you solve #abs(5.2x+7)=3.8#?

Answer 1

#x = -8/13, -27/13#

CASE 1. #color(red)(5.2x+7 >= 0)#
if #5.2x+7 >= 0# #i.e. x >= -7/5.2# or #x >= -35/26#
then #|5.2x+7| = 5.2x+7# because the modulus of a positive number is the number itself.
#therefore # in this case #5.2x+7=3.8# #=> 5.2x = -3.2# #=> x=-3.2/5.2 = color(red)(-8/13)#
CASE 2. #color(red)(5.2x+7 < 0)#
if #5.2x+7 < 0# #i.e. x < -7/5.2# or #x < -35/26#
then #|5.2x+7| = -(5.2x+7) = -5.2x-7# because the modulus of a negative number is negative of the number or in other words modulus of a negative number is obtained by multiplying the number with #-1#.
#e.g. -2<0 => |-2| = -(-2) or -1*(-2) = 2#
#therefore # in this case #-5.2x-7=3.8# #=>-5.2x = 10.8# #=> x=-10.8/5.2 = color(red)(-27/13)#
Hence, #x = color(red)(-8/13) or color(red)(-27/13)#.
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Answer 2

To solve the equation abs(5.2x + 7) = 3.8, you set up two equations by considering the positive and negative cases of the absolute value:

  1. 5.2x + 7 = 3.8
  2. -(5.2x + 7) = 3.8

Then, solve each equation separately for x:

  1. For the first equation: 5.2x + 7 = 3.8 Subtract 7 from both sides: 5.2x = 3.8 - 7 5.2x = -3.2 Divide both sides by 5.2: x = -3.2 / 5.2 x ≈ -0.615

  2. For the second equation: -(5.2x + 7) = 3.8 Distribute the negative sign: -5.2x - 7 = 3.8 Add 7 to both sides: -5.2x = 3.8 + 7 -5.2x = 10.8 Divide both sides by -5.2: x = 10.8 / -5.2 x ≈ -2.077

So, the solutions to the equation are approximately x ≈ -0.615 and x ≈ -2.077.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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