How do you solve #abs(4x+2)<6#?
See below
Use definition of absolute value
In our case
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To solve the inequality ( 4x + 2 < 6 ), you can follow these steps:

Set up two inequalities: [ \begin{align*} &4x + 2 < 6 \ &4x + 2 > 6 \end{align*} ]

Solve each inequality separately: [ \begin{align*} &4x + 2 < 6 \ &\Rightarrow 4x < 4 \ &\Rightarrow x < 1 \ \ &4x + 2 > 6 \ &\Rightarrow 4x > 8 \ &\Rightarrow x > 2 \end{align*} ]

Combine the solutions: The solution is the intersection of the two sets: [ 2 < x < 1 ]
So, the solution to ( 4x + 2 < 6 ) is ( 2 < x < 1 ).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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