How do you solve #abs(2x)<2+ abs3#?
First of all, simplify the inequality.
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To solve the inequality ( |2x| < 2 + |3| ), follow these steps:
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Split the absolute value inequalities: ( -2 < 2x < 2 + 3 )
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Simplify the inequality: ( -2 < 2x < 5 )
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Divide each part of the inequality by 2: ( -1 < x < \frac{5}{2} )
So, the solution to the inequality is ( -1 < x < \frac{5}{2} ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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