# How do you solve #abs(2/3x+2)=10#?

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To solve the equation abs(2/3x + 2) = 10:

- Start by isolating the absolute value expression: 2/3x + 2 = 10 or 2/3x + 2 = -10
- Solve each equation separately: For 2/3x + 2 = 10: Subtract 2 from both sides: 2/3x = 8 Multiply both sides by 3/2: x = 12 For 2/3x + 2 = -10: Subtract 2 from both sides: 2/3x = -12 Multiply both sides by 3/2: x = -18

So the solutions are x = 12 and x = -18.

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