How do you solve #abs(15-3x)=12#?

Answer 1

#x=1" or " x=9#

The equation has two solutions.

#"solving "15-3x=color(red)(+-)12#
#color(blue)"first solution"#
#"solve "15-3x=color(red)(+12)#

From both sides of the equation, deduct 15.

#cancel(15)cancel(-15)-3x=12-15#
#rArr-3x=-3#

divide each side by three.

#(cancel(-3) x)/cancel(-3)=(-3)/(-3)#
#rArrx=1#
#color(blue)"second solution"#
#"solve "15-3x=color(red)(-12)#
#rArr-3x=-12-15=-27#
#rArrx=(-27)/(-3)=9#
#color(magenta)"As a check"#

These values are the solutions if you substitute them into the left side of the equation and see if they equal the right side.

#• x=1to|15-(3xx1)|=|12|=12larr" true"#
#• x=9 to|15-(3xx9)|=|-12|=12larr" true"#
#rArr" solutions are "x=1" or "x=9#
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Answer 2

To solve the equation abs(15-3x) = 12:

  1. Set up two equations: 15 - 3x = 12 and 15 - 3x = -12.
  2. Solve each equation separately for x.
  3. Check the solutions to ensure they satisfy the original equation.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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