How do you solve #(a-6)/5=7/12#?

Answer 1

Avery Alexander

#a=107/12#

To obtain, cross-multiply.

#12a-72=35#

Thus

#12a=107#

#a=107/12#

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Answer 2

Ethan Adkins

#color(green)(a = 107/12 = 8 11/12#

#(a-6)/5 = 7/12#

#a-6 = (5 * 7) / 12 = 35/12#

#a = 6 + 35/12#

#a= (72 + 35) / 12#, taking L C M.

#color(green)(a = 107/12 = 8 11/12#

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Answer 3

Isaiah Anthony

To solve the equation (a - 6)/5 = 7/12, first, multiply both sides of the equation by 5 to eliminate the denominator on the left side. This gives you (a - 6) = (7/12) * 5. Next, simplify the right side of the equation to get (a - 6) = 35/12. Then, add 6 to both sides to isolate the variable a. This yields a = 35/12 + 6. Finally, simplify the expression on the right side to find the value of a.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.