How do you solve #(a+3)/a-6/(5a)=1/a#?

Answer 1

#color(blue)(a=-4/5#

#(a+3)/a-6/(5a)=1/a#
#:.(a+3)/a-1/a=6/(5a)#
#:.(a+3-1)/a=6/(5a)#
multiply L.H.S and R.H.S by #5a#
#:.(5cancela)^color(green)1/1 xx (a+3-1)/cancela^color(green)1=6/cancel(5a)^color(green)1 xx cancel (5a)^color(green)1/1 #
#:.5(a+3-1)=6#
#:.5(a+2)=6#
#5a+10=6#
#:.5a=6-10#
#:.5a=-4#
#:.color(blue)(a=-4/5#
substitute #color(blue)(a=-4/5#
#:.(-(4/5)+3)/(-4/5)-6/(5(-4/5))=1/(-4/5)#
#:.(-4/5+15/5)/(-4/5)-6/(-20/5)=1 xx -5/4#
#:.(11/5)/(-4/5)-6/-4=-5/4#
#:.11/cancel5^1 xx -cancel5^1/4=-5/4#
#:.11/-4-6/-4=-5/4#
#:.color(blue)(5/-4=5/-4#
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Answer 2

To solve the equation (a+3)/a - 6/(5a) = 1/a, we can follow these steps:

  1. Simplify the equation by finding a common denominator for the fractions. The common denominator is 5a.

  2. Multiply each term by the common denominator to eliminate the fractions.

  3. Distribute the denominator to each term in the numerators.

  4. Simplify the equation by combining like terms.

  5. Solve for 'a' by isolating it on one side of the equation.

Here are the steps in detail:

  1. The equation is: (a+3)/a - 6/(5a) = 1/a

  2. Multiply each term by the common denominator, 5a: 5a * (a+3)/a - 5a * 6/(5a) = 5a * 1/a

  3. Distribute the denominator to each term in the numerators: (5a(a+3))/a - (5a * 6)/(5a) = 5a/a

  4. Simplify the equation by canceling out common factors: 5(a+3) - 6 = 5

  5. Expand and simplify: 5a + 15 - 6 = 5

  6. Combine like terms: 5a + 9 = 5

  7. Isolate 'a' by subtracting 9 from both sides: 5a = 5 - 9

  8. Simplify: 5a = -4

  9. Solve for 'a' by dividing both sides by 5: a = -4/5

Therefore, the solution to the equation is a = -4/5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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