How do you solve #a/(2a+1) - (2a^2+5)/ (2a^2-5a-3) =3/(a-3)#?

Answer 1
Given #a/(2a+1)-(2a^2+5)/(2a^2-5a-3) = 3/(a-3)#
Noting that #2a^2-5a-3 = (2a+1)(a-3)# we can clear the denominators from the given equation by multiplying by #2a^2-5a-3#
#a(a-3) -(2a^2+5) = 3(2a+1)#
#a^2 -3a -2a^2 -5 = 6a +3#
#a^2+9a+8 =0#
Factor the left side #(a+1)(a+9) = 0#
State the solutions #a=-1# or #a=-9#
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Answer 2

To solve the equation (a/(2a+1)) - ((2a^2+5)/ (2a^2-5a-3)) = 3/(a-3), we can follow these steps:

  1. Simplify the expressions on both sides of the equation.
  2. Find a common denominator for the fractions.
  3. Combine the fractions on both sides of the equation.
  4. Solve for the variable, a.

Here are the steps in detail:

  1. Simplify the expressions:

    • The expression a/(2a+1) is already simplified.
    • For the expression (2a^2+5)/ (2a^2-5a-3), we cannot simplify it further.
  2. Find a common denominator:

    • The denominators in the two fractions are (2a+1) and (2a^2-5a-3).
    • The common denominator is (2a+1)(2a^2-5a-3).
  3. Combine the fractions:

    • Multiply the first fraction, a/(2a+1), by (2a^2-5a-3)/(2a^2-5a-3).
    • Multiply the second fraction, (2a^2+5)/ (2a^2-5a-3), by (2a+1)/(2a+1).
    • This will give us a common denominator for both fractions.
  4. Solve for the variable, a:

    • After combining the fractions, we will have a new equation.
    • Solve this equation for the variable, a.
    • The solution will be the value(s) of a that satisfy the equation.

Please note that without the specific equation, it is not possible to provide the exact solution.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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