How do you solve #a/10=2/5#?

Answer 1

#a=4#

For this problem, we need to find the LCD (least common denominator). In this case, it is #10# as
#5 * 2= 10#
If we multiply the denominator by #2#, then we also need to multiply the numerator by #2#
#2 * 2= 4#

So

#a/10 = (2 * 2)/(5 * 2)#
#a/10 = 4/10#
#a=4 #
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Answer 2

#a=4#

#color(blue)("Preamble")#
You need to manipulate the equation so that you have #a# on its own on one side of the equals sign and everything else on the other side.
The left side we have #1/10xxa# So if we can change the #1/10# into 1 we have: #1xxa# which is the same as just #a# ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ #color(blue)("Answering the question")#
Multiply both sides by #color(red)(10)#
#color(green)(a/10color(red)(xx10)" "=" " 2/5color(red)(xx10))#
#color(green)(a color(red)(xx)color(red)(10)/10" "=" " 2/5color(red)(xx10))#
But #10/10=1#
#a=4#
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Answer 3

To solve ( \frac{a}{10} = \frac{2}{5} ), you can cross multiply. Multiply 5 to both sides of the equation to eliminate the denominator. Then, solve for ( a ). So, ( a = \frac{2 \times 10}{5} ). Simplify to get ( a = 4 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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