How do you solve #9y-43=3y+71#?

Answer 1

You basically combine like terms and divide in order to solve this equation

#9y-43=3y+71# subtract 3y from both sides #6y-43=71# Now add 43 on both sides #6y=114# divide both sides by 6 #(cancel6y)/cancel6 = cancel114^19/cancel6^1# #y=19#

19 is your response.

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Answer 2

Abigail Allen

To solve 9y - 43 = 3y + 71, you first need to isolate the variable y. Add 43 to both sides of the equation to eliminate the constant term on the left side:

9y - 43 + 43 = 3y + 71 + 43 9y = 3y + 114

Next, subtract 3y from both sides to move all terms involving y to one side:

9y - 3y = 3y + 114 - 3y 6y = 114

Finally, divide both sides by 6 to solve for y:

6y / 6 = 114 / 6 y = 19

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.