How do you solve #9x+20=-16#?

Answer 1

#x=-4#

1.) First, subtract #20# from each side.
#9x + 20 -color(blue)(20) = -16 -color(blue)(20)#
2.) The #20#s cancel out on the left side. Simplify the right side (add #-16 and 20#).
#9x = -36#
3.) Now divide out #9# to finish isolating #x#.
#(9x)/(color(green)(9)) = -36/(color(green)(9)#
4.) The #9#s cancel out on the left and the right can be simplified.
#x = -4#
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Answer 2

To solve the equation 9x + 20 = -16, you first subtract 20 from both sides to isolate the term with x. This gives you 9x = -36. Then, divide both sides by 9 to solve for x. The solution is x = -4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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