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How do you solve #-9s = - 11s + 8#?

Answer 1

Abigail Allen

See a solution process below:

Step 1: Add #color(red)(11s)# to each side of the equation to isolate the #s# term while keeping the equation balanced:

#color(red)(11s) - 9s = color(red)(11s) - 11s + 8#

#(color(red)(11) - 9)s = 0 + 8#

#2s = 8#

Step 2: Divide each side of the equation by #color(red)(2)# to solve fr #s# while keeping the equation balanced:

#(2s)/color(red)(2) = 8/color(red)(2)#

#(color(red)(cancel(color(black)(2)))s)/cancel(color(red)(2)) = 4#

#s = 4#

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Answer 2

Jameson Allen

To solve the equation (-9s = -11s + 8), follow these steps:

Add (11s) to both sides to isolate (s): (-9s + 11s = 8) (2s = 8)
Divide both sides by (2) to solve for (s): (s = \frac{8}{2}) (s = 4)

Therefore, the solution to the equation is (s = 4).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.