How do you solve #92- 42x = 2x^2#?

Answer 1

#x = 2 or x = -23#

Notice that it is a quadratic equation because there is an #x^2# term. The first step is to move all the terms to one side to make the equation equal to #0#

#2x^2 +42x-92=0" "larr div 2#

#x^2 +21x-46=0" "larr# find factors if possible

#(x+23)(x-2)=0#

Either factor could be equal to #0#

#x+23 = 0 " "rarr x =-23#

#x-2=0" "rarr x = 2#

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Answer 2

Hazel Anglin

To solve the equation (92 - 42x = 2x^2), follow these steps:

Rearrange the equation to set it equal to zero: (2x^2 + 42x - 92 = 0).
Factor out any common factors, if possible. In this case, there are no common factors.
Use the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}), where (a = 2), (b = 42), and (c = -92).
Substitute the values of (a), (b), and (c) into the quadratic formula and solve for (x).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.