# How do you solve #8y^2-9y=-1#?

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or

Thus, there are various approaches to take in this:

First Method: Factoring

I'm going to start by rewriting this to equal 0. I'll do that by adding 1 to both sides.

This can be factored to become a product of two linear terms, which will facilitate the solution process. The result will be written as follows:

The derivation comes from expanding that into: to determine each value.

Therefore, we desire the following claims to be accurate:

The statement can only be true if both b and d have values of +1 or -1. Based on the -9 in the center, I can conclude that both b and d should be -1.

Thus, we currently have the following feature:

We can solve for y by applying the 0 product principle, which states that any number multiplied by 0 is 0. All we need is for one of them to be 0. In this instance, our solutions are as follows:

Step 2: Use the Quadratic Formula

The Quadratic Formula can be used in the event that factoring is ineffective. It states that as a function of:

The following address will have the solutions:

We'll begin by adding 1 to both sides of our function:

Now let's enter the values.

And there you have your answer in two ways: if you have a calculator, you could graph it, but if not, there are two ways to do it.

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To solve (8y^2 - 9y = -1), you can use the quadratic formula or factorization.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- How do you solve #4(6x-1)^2-5=223#?

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