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How do you solve #8x-(x-5)>x+17#?

Answer 1

#x > 2#

Given #color(white)("XXX")8x-(x-5) > x+17#

Remember that valid operations that maintain the validity and direction of an inequality include: a) addition or subtraction of the same amount to both sides; b) multiplication or division of both sides by the same amount provided that amount is greater than zero.

#rArr# #color(white)("XXX")7x+5 > x+17#

#color(white)("XXX")6x > 12#

#color(white)("XXX")x > 2#

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Answer 2

Ethan Adkins

To solve the inequality 8x - (x - 5) > x + 17, follow these steps:

Distribute the negative sign through the parentheses: 8x - x + 5 > x + 17
Combine like terms: 7x + 5 > x + 17
Subtract x from both sides: 6x + 5 > 17
Subtract 5 from both sides: 6x > 12
Divide both sides by 6: x > 2

So the solution to the inequality is x > 2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve #8x-(x-5)&gt;x+17#?

How do you solve #8x-(x-5)>x+17#?