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How do you solve #(8x-9)^2=6#?

Answer 1

Eva Adamson

#x = 1.431" and "x =0.819#

If you had an equation such as #x^2 = 25,#

you could solve it easily by taking the square root of both sides:

#x = +-sqrt25 = +-5#

The given equation is in exactly the same form:

#(8x-9)^2 =6" "larr# take the square root of both sides

#8x-9 = +-sqrt6" "larr# remember there are two roots

#8x = +-sqrt6 +9#

This will give us two answers:

#x = (+sqrt6+9)/8" and "x = (-sqrt6+9)/8#

#x = 1.431" and "x =0.819#

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Answer 2

Julia Adams

To solve (8x - 9)^2 = 6, expand the expression (8x - 9)^2, set it equal to 6, and then solve for x. After expanding, the equation becomes a quadratic equation, which can be solved using algebraic techniques such as factoring, completing the square, or using the quadratic formula. Once the quadratic equation is solved, any solutions for x can be verified by substitution into the original equation to ensure they satisfy the equation.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.