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How do you solve #8x + 3= 19#?

Answer 1

#x=2#

When tackling linear algebraic equations such as these, any action taken on one side must also be taken on the other.

What we want to do is get "x" by itself on its side of the equation. If this is done correctly, the equation will look like "#x=#number" where the "number" is the answer.

Following the procedure:

First subtract 3 from both sides (whatever you do to one side to do the other) #8x+3=19# #(8x+3)-3=19-3# The 3's cancel out on the left side of the = sign, and do 19 minus 3 on the other side. #8x=16#

Now, divide 8 from both sides. Remember, we're trying to get the "x" value all by itself. #8x=16# #(8x)/8=16/8# The 8's reduce to 1 on the left side of the = sign, and do 16 divided by 8 on the other side. #(1)x=2# #x=2#

I hope this was helpful; sometimes I struggle to explain things as clearly as I can!

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Answer 2

Savannah Anderson

To solve 8x + 3 = 19, you need to isolate the variable x by subtracting 3 from both sides and then dividing both sides by 8. So, the steps are:

8x + 3 - 3 = 19 - 3
8x = 16
Divide both sides by 8: 8x/8 = 16/8

The solution is x = 2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.