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How do you solve #-8v + 4( v - 2) = - 32#?

Answer 1

Savannah Anderson

#v=6#

Multiply #4# through the brackets,

#-8v+4v-8=-32#

Gather similar terms,

#-4v=-24#

Divide both sides by #-4#,

#v=6#

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Answer 2

Isaiah Anthony

#v=6#

See the process in the explanation.

Resolve:

#-8v+4(v-2)=-32#

Extend.

#-8v+4v-8=-32#

Add #8# to both sides of the equation.

#-8v+4v-color(red)cancel(color(black)(8))+color(red)cancel(color(black)(8))=-32+8#

Make it simple.

#-4v=-24#

Divide both sides by #-4#.

#color(red)cancel(color(black)(-4v))/color(red)cancel(color(black)(-4))=color(red)cancel(color(black)(-24))^color(blue)6/color(red)cancel(color(black)(-4)^color(blue)1#

Make it simple.

#v=6#

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Answer 3

Jameson Allen

To solve the equation -8v + 4(v - 2) = -32:

Distribute the 4 across the parentheses: -8v + 4v - 8 = -32.
Combine like terms: -4v - 8 = -32.
Add 8 to both sides: -4v = -24.
Divide both sides by -4: v = 6.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.