How do you solve #8m^2 - 2m = 7# using the quadratic formula?
See a solution process below:
The equation should first be put in standard form:
The quadratic equation can now be used to solve this problem:
According to the quadratic formula,
Replacing:
The Set of Solutions Is:
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To solve the equation 8m^2 - 2m = 7 using the quadratic formula, follow these steps:
-
Identify the coefficients of the quadratic equation:
- (a = 8)
- (b = -2)
- (c = -7)
-
Substitute the values of (a), (b), and (c) into the quadratic formula: [m = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}]
-
Plug in the values: [m = \frac{{-(-2) \pm \sqrt{{(-2)^2 - 4(8)(-7)}}}}{{2(8)}}]
-
Simplify inside the square root: [m = \frac{{2 \pm \sqrt{{4 + 224}}}}{{16}}] [m = \frac{{2 \pm \sqrt{{228}}}}{{16}}]
-
Further simplify: [m = \frac{{2 \pm 2\sqrt{57}}}{{16}}]
-
Divide numerator and denominator by 2: [m = \frac{{1 \pm \sqrt{57}}}{{8}}]
Therefore, the solutions for the equation (8m^2 - 2m = 7) using the quadratic formula are: [m = \frac{{1 + \sqrt{57}}}{{8}} \text{ and } m = \frac{{1 - \sqrt{57}}}{{8}}]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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