How do you solve #8k - 3( k - 5) = 45#?

Answer 1

See a solution process below:

First, expand the terms in parenthesis on the left side of the equation by multiplying each term within the parenthesis by the term outside the parenthesis:

#8k - color(red)(3)(k - 5) = 45#
#8k - (color(red)(3) xx k) - (color(red)(3) xx -5) = 45#
#8k - 3k - (-15) = 45#
#8k - 3k + 15 = 45#
#(8 - 3)k + 15 = 45#
#5k + 15 = 45#
Next, subtract #color(red)(15)# from each side of the equation to isolate the #k# term while keeping the equation balanced:
#5k + 15 - color(red)(15) = 45 - color(red)(15)#
#5k + 0 = 30#
#5k = 30#
Now, divide each side of the equation by #color(red)(5)# to solve for #k# while keeping the equation balanced:
#(5k)/color(red)(5) = 30/color(red)(5)#
#(color(red)(cancel(color(black)(5)))k)/cancel(color(red)(5)) = 6#
#k = 6#
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Answer 2

To solve the equation 8k - 3(k - 5) = 45, first distribute the -3 across the parentheses to get 8k - 3k + 15 = 45. Then, combine like terms to get 5k + 15 = 45. Next, isolate the variable by subtracting 15 from both sides to get 5k = 30. Finally, divide both sides by 5 to solve for k, which gives k = 6.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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