How do you solve #8/(b+10)=4/(2b-7)#?

Answer 1

Abigail Allen

#b=8#

First, multiply the two fractions by a cross.

#8(2b-7)=4(b+10)#

Use the distributive property to both sides of the equations in step two.

#16b-56=4b+40#

Step 3: add #56# to both sides

#16b-56+56=4b+40+56#

#16b=4b+96#

Step 4: Subtract #4b# on both sides of the equation to isolate the variable

#12b=96#

Step 5: Separate and make simpler

#b=8#

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Answer 2

Julia Adams

To solve the equation 8/(b+10) = 4/(2b-7), cross multiply to get 8(2b-7) = 4(b+10). Simplify both sides to get 16b - 56 = 4b + 40. Move the terms to isolate the variable, resulting in 16b - 4b = 40 + 56. Combine like terms to get 12b = 96. Finally, divide both sides by 12 to solve for b, yielding b = 8.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.