How do you solve #-8-8p^2=-31#?

Answer 1

Eva Abramson

#p=+-sqrt(23/8) ~= +- 1.69558#

#-8-8p^2 = -31#

Multiply through by #-1#

#8+8p^2 = 31#

#8p^2 = 31-8 =23#

#p^2 = 23/8#

#p = +- sqrt(23/8) ~=+- 1.69558#

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Answer 2

Eli Assouline

Rearrange your exquation to give #p=+-sqrt(23/8)#

#-8-8p^2=-31# #-8p^2=-23# #p^2=23/8# #p=+-sqrt(23/8)#

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Answer 3

Jace Anderson

To solve the equation -8 - 8p^2 = -31, first, add 8 to both sides to isolate the term with the variable:

-8p^2 = -23

Then, divide both sides by -8:

p^2 = 23/8

To solve for p, take the square root of both sides, remembering to consider both the positive and negative square roots:

p = ±√(23/8)

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.