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How do you solve #8-8a^2=-792#?

Answer 1

Nathan Axel

#a = +-10#

#8-8a^2= -792#

#8a^2 = 800#

#a^2 = 100#

#a = +-sqrt100#

#a = +-10#

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Answer 2

Nathan Axel

#a=±10#

What we want to do here is isolate the #-8a^2# term on the left side of the equation while having the numeric value on the right.

To do this subtract 8 from both sides.

#cancel(8)cancel(-8)-8a^2=-792-8#

#rArr-8a^2=-800#

now divide both sides by -8

#(cancel(-8)^1 a^2)/cancel(-8)=(cancel(-800)^(100))/cancel(-8)^1rArra^2=100#

now take the 'square root' of both sides

#sqrt(a^2)=±sqrt100rArra=±10#

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Answer 3

Savannah Anderson

To solve the equation ( 8 - 8a^2 = -792 ), first, add ( 8 ) to both sides to isolate the term with the variable. Then, divide both sides by ( -8 ) to solve for ( a^2 ). Finally, take the square root of both sides to solve for ( a ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.