How do you solve #8- 5y > - 37#?

Answer 1

#y < 9#

#8 - 5y > -37#

Equation solving and inequalities solving are very similar.

First, both sides of the inequality should have #color(blue)(-37)# added to them: #8 - 5y quadcolor(blue)(+quad37) > -37 quadcolor(blue)(+quad37)#
#45 - 5y > 0#
To both sides of the inequality, add #color(blue)(5y)#: #45 - 5y quadcolor(blue)(+quad5y) > 0 quadcolor(blue)(+quad5y)#
#45 surpasses 5y#
Apply #color(blue)(5)# to both sides now: #45/color(blue)5 > (5y)/color(blue)5#
#9 is greater than y#
But we still want our variable #y# to be less than #9#, so we want it to be on the left side, so it is: #y < 9#.

I hope this is useful.

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Answer 2

To solve the inequality 8 - 5y > -37, follow these steps:

  1. Subtract 8 from both sides to isolate the term with the variable: 8 - 5y - 8 > -37 - 8 -5y > -45

  2. Divide both sides by -5 to solve for y: (-5y) / (-5) < (-45) / (-5) y < 9

So, the solution to the inequality is y < 9.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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