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How do you solve #8/(5x-4)=6/(x+5)#?

Answer 1

Nathan Axel

#x in {32/11}#

#8(x+5) = 6(5x - 4)#

#4x+20 = 15x - 12#

#32 = 11x#

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Answer 2

Jameson Allen

To solve the equation 8/(5x - 4) = 6/(x + 5), cross multiply to eliminate the denominators. This gives 8(x + 5) = 6(5x - 4). Then distribute and solve for x. This results in 8x + 40 = 30x - 24. Next, move variables to one side and constants to the other. This gives 24 = 22x - 40. Now, add 40 to both sides to isolate the variable term. This gives 64 = 22x. Finally, divide both sides by 22 to solve for x. Thus, x = 64/22 or x = 32/11.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.