How do you solve #8- 5[ 6- ( 8- 10) ] \div ( - 2)^{3}#?

Answer 1

#13#

(Note that this is an expression not an equation, so it is simplified rather than solved, which means to find the value of a variable.)

Always count the number of terms first. Each term will simplify to a single answer and these will be added or subtracted in the last step.

Within each term, brackets get done first, followed by powers and roots and finally multiplication and division.

There are 2 terms in this expression. Keep them separate until the last step.

#color(magenta)(8)- 5[ 6- ( color(red)(8- 10)) ] \div color(red)(( - 2)^{3})#
=#color(magenta)8- 5[ color(blue)(6-color(red)( ( -2))) ] \div (color(red)(- 8))#
=#color(magenta)8- 5[ color(blue)(6+2) ] \div (- 8)#
=#color(magenta)8- 5[ color(blue)(8) ] \div (- 8)#
=#color(magenta)8color(lime)(- 40 div (- 8))#
=#color(magenta)8color(lime)(+5)#
=#13#
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Answer 2
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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