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How do you solve #8(2w-6) + 4 (-1 - 5w)= 0#?

Answer 1

Isaiah Anthony

# w = - 13#

#8 ( 2w - 6) + 4 ( - 1 - 5w) = 0#

#8 * ( 2w) + 8 * ( - 6) + 4 * ( - 1) + 4 * ( - 5w) = 0#

# 16w - 48 - 4 - 20 w = 0#

# (16w - 20w) - 4 - 48 = 0#

# - 4w - 52 = 0#

# - 4w = 52#

# w = 52 / (-4)#

# w = - 13#

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Answer 2

Abigail Allen

To solve the equation 8(2w - 6) + 4(-1 - 5w) = 0, you first distribute the numbers outside the parentheses:

8(2w - 6) = 16w - 48 4(-1 - 5w) = -4 - 20w

Then, you combine like terms:

16w - 48 - 4 - 20w = 0 (16w - 20w) + (-48 - 4) = 0 -4w - 52 = 0

Next, you isolate the variable by adding 52 to both sides:

-4w - 52 + 52 = 0 + 52 -4w = 52

Then, you divide both sides by -4 to solve for w:

-4w / -4 = 52 / -4 w = -13

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.