How do you solve #8( 2 x ) = \frac { 4} { 5} ( x + 52)#?
Move all of the constants to one side of the equation with algebraic operations.
 To obtain all of the factors, multiply the given values.
16 + 8x = (0.8)x + 41.6; −8(2−x) = (4/5)(x+52)
 Add 16 to each side, then deduct 0.8x from each side.
7.2x = 57.6; 8x = 0.8x + 57.6
 Apply 7.2 to both sides.
x = 8
Reenter the original expression with the solution to verify if it is correct: −8(2−(8)) = (4/5)(8+52); 8(6) = (4/5)(60); 48 = 48
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To solve the equation (8(2  x) = \frac{4}{5}(x + 52)), we can follow these steps:

Distribute the coefficients on both sides of the equation: (16 + 8x = \frac{4}{5}x + \frac{208}{5})

Move all terms involving x to one side of the equation and constants to the other side: (16 + 16x = \frac{4}{5}x + \frac{208}{5} + 16)

Combine like terms: (16x  \frac{4}{5}x = \frac{208}{5} + 16  16)

Simplify the equation further: (\frac{76}{5}x = \frac{288}{5})

Solve for x by multiplying both sides by the reciprocal of (\frac{76}{5}), which is (\frac{5}{76}): (x = \frac{\frac{288}{5} \cdot \frac{5}{76}}{\frac{76}{5}})

After simplifying, we get: (x = \frac{72}{19})
So, the solution to the equation is (x = \frac{72}{19}).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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