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How do you solve #7x - 5 = 6x + 6#?

Answer 1

#x = 11#

#7x - 5 = 6x + 6#

To find the variable #x#, we have to make it by itself.

To do so, first add #color(blue)5# to both sides of the equation: #7x - 5 quadcolor(blue)(+quad5) = 6x + 6 quadcolor(blue)(+quad5)#

#7x = 6x + 11#

Now subtract #color(blue)(6x)# from both sides of the equation: #7x quadcolor(blue)(-quad6x) = 6x + 11 quadcolor(blue)(-quad6x)#

Therefore, #x = 11#

Hope this helps!

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Answer 2

Julia Adams

To solve the equation 7x - 5 = 6x + 6, we need to isolate the variable x on one side of the equation. First, we can subtract 6x from both sides to get rid of the variable from the right side of the equation. This gives us: 7x - 6x - 5 = 6. Simplifying this, we have x - 5 = 6. Next, we add 5 to both sides of the equation to isolate the variable x. This gives us: x - 5 + 5 = 6 + 5. Simplifying further, we get x = 11. So, the solution to the equation 7x - 5 = 6x + 6 is x = 11.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.