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How do you solve #7x-4(2-3x) = 3x-6+8x#?

Answer 1

Ethan Adkins

#x = 0.25#

Try to shift all the expressions to one side

#7x-4(2-3x)-3x+6-8x=0#

Expand the brackets and add all like terms

#7x-8+12x-3x+6-8x=0#

#8x-2=0#

Make x the subject

#x =2/8#

#x = 0.25#

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Answer 2

Abigail Allen

To solve the equation (7x - 4(2 - 3x) = 3x - 6 + 8x), follow these steps:

Distribute the -4 inside the parentheses: (7x - 8 + 12x = 3x - 6 + 8x).
Combine like terms on both sides of the equation: (7x + 12x - 8 = 3x + 8x - 6).
Simplify each side: (19x - 8 = 11x - 6).
Move variables to one side and constants to the other side: (19x - 11x = -6 + 8).
Simplify: (8x = 2).
Solve for (x): (x = \frac{2}{8}).
Simplify the fraction: (x = \frac{1}{4}).

So, the solution to the equation is (x = \frac{1}{4}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.