How do you solve #7x + 3( x - 1) = 3+ 4( 1+ 2x )#?

Answer 1

#x=5#

The first step to solving this problem (if we refer to PEMDAS) will be parentheses. To get rid of our parentheses, we need to distribute the term in front of them to every term inside. After distributing, we get: #7x+3x-3=3+4+8x#
Then, we need to combine like terms. Remember that you can only combine like terms if they're on the same side of the equal sign. So, we get: #10x-3=7+8x #
Finally, we need to solve for #x#. There are a few ways you can go about this step, but I would subtract #8x# from both sides of the equation (whatever you do to one side, you must do to the other). We are then left with: #2x-3=7#
Add #3# to both sides: #2x=10#
Divide by #2#: #x=5#
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Answer 2

To solve the equation (7x + 3(x - 1) = 3 + 4(1 + 2x)), first, distribute the terms inside the parentheses. Then combine like terms on both sides of the equation. Afterward, isolate the variable (x) by performing the necessary operations. Finally, solve for (x).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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