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How do you solve #7s-29=-15#?

Answer 1

#s=2#

Step 1: Have only the 'parts' with s in them on the left of the = and #" "#everything else on the other side.

Step 2: Have only s on the left of = and everything else on the #" "#other side. ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Step 1:

Add #color(red)(29)# to both sides

#color(green)(7s-29=-15" "->" "7s-29color(red)(+29)=-15color(red)(+29#

#" "color(green)(7s+0=14)#

Step 2: Multiply both sides by #color(red)(1/7)#

#" "color(green)(7/(color(red)(7))s=14/(color(red)(7)))#

But #7/7=1 and 14/7=2# giving:

#" "color(green)(s=2)#

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Answer 2

Eva Adamson

To solve the equation 7s - 29 = -15, you would first add 29 to both sides of the equation to isolate the variable term. This gives you 7s = 14. Then, divide both sides by 7 to solve for s. So, s = 2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.