How do you solve #(7k/8)  (3/4)  (5k/16) = (3/8)#?
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To solve the equation (\frac{7k}{8}  \frac{3}{4}  \frac{5k}{16} = \frac{3}{8}), follow these steps:

Find a common denominator for the fractions involved: The denominators here are 8, 4, 16, and 8. The least common denominator (LCD) is 16.

Express all fractions with the common denominator (16):
 (\frac{7k}{8} = \frac{14k}{16}) (by multiplying both numerator and denominator by 2),
 (\frac{3}{4} = \frac{12}{16}) (by multiplying both numerator and denominator by 4),
 (\frac{5k}{16}) remains unchanged since its denominator is already 16,
 (\frac{3}{8} = \frac{6}{16}) (by multiplying both numerator and denominator by 2).

Rewrite the equation with these equivalents: [\frac{14k}{16}  \frac{12}{16}  \frac{5k}{16} = \frac{6}{16}]

Combine like terms:
 Combine the k terms: (\frac{14k}{16}  \frac{5k}{16} = \frac{9k}{16}).
 The equation now is (\frac{9k}{16}  \frac{12}{16} = \frac{6}{16}).

Solve for k:
 First, isolate the k term by adding (\frac{12}{16}) to both sides of the equation: [\frac{9k}{16} = \frac{6}{16} + \frac{12}{16}] [\frac{9k}{16} = \frac{18}{16}]
 Then, solve for k by multiplying both sides by the reciprocal of (\frac{9}{16}) (which is (\frac{16}{9})): [k = \frac{18}{16} \times \frac{16}{9}] [k = \frac{18}{9}] [k = 2]
So, (k = 2).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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