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How do you solve #7( x - 3) = 2( x - 9) + 2x#?

Answer 1

Ethan Adkins

#x=1 #

Initially, we would bring the outside number in to open the bracket on one side;

#7 times x=7x" "# and #" "7 times -3= -21#

Additionally, since the left side is being subtracted, we would get

#7x-21#

As we proceed to the right, we would first open the bracket, providing us with

#2x-18+2x#

then we would sub #4x# from the right side because #2x+2x# gives us #4x#, then we would take that #4x# and sub it to the #7x# giving us

#3x-21=-18#

Then we would add #21# to the right side because were subtracting on the left side. That would give us

#3x=3#

and to get #x# by itself, we would divide the #3# from both sides giving us a final answer of........

#x=1#

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Answer 2

Eli Assouline

To solve the equation (7(x - 3) = 2(x - 9) + 2x), first distribute the terms inside the parentheses, then combine like terms, and finally isolate the variable (x).

(7x - 21 = 2x - 18 + 2x)

Combine like terms:

(7x - 21 = 4x - 18)

Subtract (4x) from both sides:

(3x - 21 = -18)

Add (21) to both sides:

(3x = 3)

Divide both sides by (3):

(x = 1)

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Answer from HIX Tutor

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