How do you solve #7 s - 2/3 - 3s - 16/6 = 2#?

Answer 1

#color(green)(s=4/3)#

Group variable terms on the left and constant terms on the right #color(white)("XXX")7s-3s=2+2/3+(cancel(16)^8)/(cancel(6)_3)#
Simplify both sides: #color(white)("XXX")4s=6/3+2/3+8/3=16/3#
Divide both sides by #4# to reduce the left side to a unit variable #color(white)("XXX")s=4/3#
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Answer 2

To solve the equation (7s - \frac{2}{3} - 3s - \frac{16}{6} = 2), follow these steps:

  1. Combine like terms: Both the (s) terms and the constant terms (fractions) can be combined.
  • Combine the (s) terms: (7s - 3s = 4s).
  • Simplify the fractions: (-\frac{2}{3} - \frac{16}{6}). Since (\frac{16}{6}) can be simplified to (\frac{8}{3}), the expression becomes (-\frac{2}{3} - \frac{8}{3} = -\frac{10}{3}).

This simplifies the equation to (4s - \frac{10}{3} = 2).

  1. Isolate the variable term: Move the constant term to the other side of the equation by adding (\frac{10}{3}) to both sides.

[4s = 2 + \frac{10}{3}]

To combine the constants, convert 2 to a fraction with a denominator of 3: (2 = \frac{6}{3}). So,

[4s = \frac{6}{3} + \frac{10}{3} = \frac{16}{3}]

  1. Solve for (s): Divide both sides by 4 to isolate (s).

[s = \frac{\frac{16}{3}}{4} = \frac{16}{3} \times \frac{1}{4} = \frac{16}{12} = \frac{4}{3}]

Thus, (s = \frac{4}{3}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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