How do you solve #7\frac { 3} { 7}+ 5\frac { 2} { 3}#?

Answer 1

See a solution process below:

First, rewrite the expression as:

#(7 + 3/7) + (5 + 2/3) =>#
#7 + 3/7 + 5 + 2/3 =>#
#7 + 5 + 3/7 + 2/3 =>#
#12 + 3/7 + 2/3#
To add the fractions we must put them over a common denominator by multiplying each fraction by the appropriate form of #1#:
#12 + (3/3 xx 3/7) + (7/7 xx 2/3) =>#
#12 + (3 xx 3)/(3 xx 7) + (7 xx 2)/(7 xx 3) =>#
#12 + 9/21 + 14/21 =>#
#12 + (9 + 14)/21 =>#
#12 + 23/21#

Now, we can convert the improper fraction to a mixed number:

#12 + (21 + 2)/21 =>#
#12 + 21/21 + 2/21 =>#
#12 + 1 + 2/21 =>#
#13 + 2/21 =>#
#13 2/21#
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Answer 2

To solve (7\frac{3}{7} + 5\frac{2}{3}), convert each mixed number to an improper fraction, then add:

  1. Convert (7\frac{3}{7}) to an improper fraction: [7\frac{3}{7} = \frac{7 \times 7 + 3}{7} = \frac{49 + 3}{7} = \frac{52}{7}]

  2. Convert (5\frac{2}{3}) to an improper fraction: [5\frac{2}{3} = \frac{5 \times 3 + 2}{3} = \frac{15 + 2}{3} = \frac{17}{3}]

  3. Add the two fractions: [\frac{52}{7} + \frac{17}{3}]

To add, find a common denominator, which is (21) here: [\frac{52}{7} \times \frac{3}{3} + \frac{17}{3} \times \frac{7}{7} = \frac{156}{21} + \frac{119}{21}]

  1. Add the fractions: [\frac{156 + 119}{21} = \frac{275}{21}]

To simplify, notice that 275 and 21 have no common factors other than 1, so the answer is: [\frac{275}{21}]

This is the final answer in improper fraction form. If you prefer a mixed number, divide 275 by 21: [275 \div 21 = 13 \text{ remainder } 2]

So, the answer as a mixed number is: [13\frac{2}{21}]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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