How do you solve #7\frac { 3} { 7}+ 5\frac { 2} { 3}#?
See a solution process below:
First, rewrite the expression as:
Now, we can convert the improper fraction to a mixed number:
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To solve (7\frac{3}{7} + 5\frac{2}{3}), convert each mixed number to an improper fraction, then add:

Convert (7\frac{3}{7}) to an improper fraction: [7\frac{3}{7} = \frac{7 \times 7 + 3}{7} = \frac{49 + 3}{7} = \frac{52}{7}]

Convert (5\frac{2}{3}) to an improper fraction: [5\frac{2}{3} = \frac{5 \times 3 + 2}{3} = \frac{15 + 2}{3} = \frac{17}{3}]

Add the two fractions: [\frac{52}{7} + \frac{17}{3}]
To add, find a common denominator, which is (21) here: [\frac{52}{7} \times \frac{3}{3} + \frac{17}{3} \times \frac{7}{7} = \frac{156}{21} + \frac{119}{21}]
 Add the fractions: [\frac{156 + 119}{21} = \frac{275}{21}]
To simplify, notice that 275 and 21 have no common factors other than 1, so the answer is: [\frac{275}{21}]
This is the final answer in improper fraction form. If you prefer a mixed number, divide 275 by 21: [275 \div 21 = 13 \text{ remainder } 2]
So, the answer as a mixed number is: [13\frac{2}{21}]
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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