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How do you solve #7( 4x + 2) + 3= - 67#?

Answer 1

See the entire solution process below:

Initially, multiply each term inside the parenthesis by the term outside the parenthesis to enlarge the terms enclosed in parenthesis on the left side of the equation:

#color(red)(7)(4x + 2) + 3 = -67#

#(color(red)(7) * 4x) + (color(red)(7) * 2) + 3 = -67#

#28x + 14 + 3 = -67#

#28x + 17 = -67#

Next, subtract #color(red)(17)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#28x + 17 - color(red)(17) = -67 - color(red)(17)#

#28x + 0 = -84#

#28x = -84#

Now, divide each side of the equation by #color(red)(28)# to solve for #x# while keeping the equation balanced:

#(28x)/color(red)(28) = -84/color(red)(28)#

#(color(red)(cancel(color(black)(28)))x)/cancel(color(red)(28)) = -3#

#x = -3#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.