How do you solve #7/3=(2x+5)/x#?
You can eliminate fractions from an equation by cross-multiplying it if it has only one term on each side, at least one of which is a fraction.
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To solve the equation 7/3 = (2x + 5) / x, you can cross multiply to eliminate the fractions.
This gives you: 7x = 3(2x + 5).
Expanding and simplifying: 7x = 6x + 15.
Then, subtract 6x from both sides: 7x - 6x = 15.
This simplifies to: x = 15.
So, the solution to the equation is x = 15.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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