How do you solve #7( 2x - 1) = 5( x - 14)#?

Answer 1

#x=-7#

Expand the brackets

#14x-7=5x-70#
Subtract #5x# from both sides
#9x-7=-70#
Add #7#to both sides
#9x=-63#
Divide both sides by #9#
#x=-7#
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Answer 2

#x=-7#

#7(2x-1)=5(x-14)#
Distribute and multiply #7# to #2x# and #-1# to get
#14x-7=#
Then distribute and multiply #5# to #x# and #-14# to get
#=5x-70#

Put together, it will look like this

#14x-7=5x-70#
Then add #70# to #-70# and #-7# to get
#14x+63=5x#
Then subtract #14x# from #14x# and #5x# to get
#63=-9x#
Divide by #-9# on both sides to get
#-7=x#
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Answer 3

See solution below:

First expand out the brackets: #7(2x-1) = 14x -7# and #5(x-14) = 5x - 70#
Hence, the equation becomes: #14x-7=5x-70#
Now rearrange to make #x# the subject:
Subtract #5x# from both sides to obtain: #=> 14x-5x-7=5x-5x-70# #=> 9x-7=70#
Then add 7 to both sides to isolate #x# #=> 9x-7+7=-70+7# #=> 9x = -63#
Finally, divide both sides by 9 to obtain #x# #=> x=-63/9#
Hence, #x=-7#
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Answer 4

To solve the equation 7(2x - 1) = 5(x - 14), first distribute the numbers outside the parentheses:

14x - 7 = 5x - 70

Next, move all terms involving x to one side of the equation and constants to the other side:

14x - 5x = -70 + 7

Combine like terms:

9x = -63

Now, isolate x by dividing both sides of the equation by 9:

x = -63 / 9

Simplify:

x = -7

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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