How do you solve #7-2w/31#?

Question

How do you solve #7-2w/3>1#?

Hazel Anglin · Accepted Answer

w < 9 Work backwards to solve for w

The process is called PEMDAS. To locate something lost, work backwards using PE SAD M. For example, if you find your cell phone missing in PE, you are a SAD M(am) M,(an). Since you are working backwards, the subtraction and addition must be completed first. There are no parenthesis or exponents in this inequality, so they must be completed first. To move the 7 away from the w subtract 7 from both sides. 7 - 7 #- 2 xx (w/3) > 1# -7 this gives t # - 2 xx (w/3) # > -6 The opposite of multiplying by 2 is dividing by 2 so # -2/2 xx (w/3) # > # -6/2# This gives # - w/3# > -3 The opposite of dividing by 3 is multiplying by 3 so # 3 xx - (w/3) # > # -3 xx 3# This gives The opposite of multiplying by -1 is dividing by -1 so # -1 / -1 xx w # # >/-1# # -9/ -1# # -1/-1# = 1 # >/-1 # = < The opposite of > is < so dividing by negative means doing the opposite, so the > becomes a < # -9/-1 # = 9 so w < 9 remember a negative means the opposite so the opposite of -9 is + 9 the opposite of > is <

Eli Assouline · Answer

undefined To solve 7 - (2w/3) > 1, first, isolate the term with the variable w, then solve for w.

How do you solve #7-2w/3&gt;1#?

How do you solve #7-2w/3>1#?