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How do you solve #-6y - 3 = 3 - 6y#?

Answer 1

Avery Alexander

See a solution process below:

First, add #color(red)(6y)# to each side of the equation:

#color(red)(6y) - 6y - 3 = 3 - 6y + color(red)(6y)#

#0 - 3 = 3 - 0#

#-3 != 3#

Because #-3# is not equal to #3# there is no solution to this equation. Or, the solution is the empty or null set: #{O/}#

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Answer 2

Kennedy Adams

There is no solution to this equation and therefore

#x# has no value.

Put the numbers on one side of the equation and all the variables on the other:

#-6y -3 = 3-6y#

#-6y +6y = 3+3#

#" "0 = 6" "larr?????????#

The result is a clearly false statement for which there is no variable.

This suggests that there is no solution to the equation and that it cannot be solved.

#x# has no value.

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Answer 3

Isaiah Anthony

To solve -6y - 3 = 3 - 6y, you can add 6y to both sides of the equation, which eliminates the variable terms. This results in -3 = 3, which is not a true statement. Therefore, the equation has no solution.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.