How do you solve #6x + 5y = -12# and #-9x + y = 69# using substitution?
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To solve the system of equations (6x + 5y = -12) and (-9x + y = 69) using substitution, follow these steps:
- Solve one of the equations for one variable in terms of the other variable.
- Substitute the expression found in step 1 into the other equation.
- Solve the resulting equation for the remaining variable.
- Once you have found the value of one variable, substitute it back into one of the original equations to find the value of the other variable.
- Check the solution by substituting the values of both variables into both original equations.
Let's start with the given equations:
- (6x + 5y = -12)
- (-9x + y = 69)
Let's solve the second equation for (y):
(-9x + y = 69)
(y = 9x + 69)
Now, substitute (9x + 69) for (y) in the first equation:
(6x + 5(9x + 69) = -12)
Now, solve for (x):
(6x + 45x + 345 = -12)
(51x + 345 = -12)
(51x = -12 - 345)
(51x = -357)
(x = -\frac{357}{51})
(x = -7)
Now that we have found the value of (x), let's substitute it back into one of the original equations to find (y). We'll use the second equation:
(-9(-7) + y = 69)
(63 + y = 69)
(y = 69 - 63)
(y = 6)
So, the solution to the system of equations is (x = -7) and (y = 6).
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To solve the system of equations (6x + 5y = -12) and (-9x + y = 69) using substitution, follow these steps:
-
Solve one of the equations for one of the variables. We can start with the second equation for ease: [-9x + y = 69] Solve for (y): [y = 9x + 69]
-
Substitute the expression for (y) into the first equation: [6x + 5(9x + 69) = -12]
-
Distribute and solve for (x): [6x + 45x + 345 = -12] [51x = -12 - 345] [51x = -357] [x = -7]
-
Substitute the value of (x) back into one of the original equations to solve for (y). Using (y = 9x + 69): [y = 9(-7) + 69] [y = -63 + 69] [y = 6]
Therefore, the solution to the system of equations is (x = -7) and (y = 6).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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