# How do you solve #-6x^2-9x+2=0# using the quadratic formula?

x=-1.696484724

or

x=0.1964847243

or

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To solve the quadratic equation (-6x^2 - 9x + 2 = 0) using the quadratic formula, we identify the coefficients: (a = -6), (b = -9), and (c = 2). Then, we plug these values into the quadratic formula:

[x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}.]

Substituting the values, we get:

[x = \frac{{-(-9) \pm \sqrt{{(-9)^2 - 4(-6)(2)}}}}{{2(-6)}}.]

[x = \frac{{9 \pm \sqrt{{81 + 48}}}}{{-12}}.]

[x = \frac{{9 \pm \sqrt{{129}}}}{{-12}}.]

So, the solutions are:

[x = \frac{{9 + \sqrt{{129}}}}{{-12}}]

[x = \frac{{9 - \sqrt{{129}}}}{{-12}}.]

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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