How do you solve #6x^2 + 8x = 14#?

Answer 1

This equation has 2 real solutions: #x_1=-2 1/3# and #x_2=1#

Before further calculations you have to move #14# to the left:
#6x^2+8x-14=0#
Now you can divide both sides by #2#:
#3x^2+4x-7=0#

Now you can calculate the discriminant:

#Delta=4^2-4*3*(-7)=16+84=100# #sqrt(Delta)=10#
#x_1=(-b-sqrt(Delta))/(2*a)=(-4-10)/(2*3)=-14/6=-2 1/3#
#x_2=(-b+sqrt(Delta))/(2*a)=(-4+10)/(2*3)=6/6=1#
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Answer 2

To solve the equation 6x^2 + 8x = 14, follow these steps:

  1. Move all terms to one side of the equation to set it equal to zero. 6x^2 + 8x - 14 = 0

  2. Factor out any common factors, if possible. The equation cannot be factored directly.

  3. Use the quadratic formula to find the solutions for x: x = [-b ± √(b^2 - 4ac)] / (2a)

    In this equation, a = 6, b = 8, and c = -14.

  4. Plug in the values of a, b, and c into the quadratic formula and solve for x.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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