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How do you solve #6s-4=8(2+1/4s)#?

Answer 1

Nathan Axel

#s = 5#

First, expand the term in parenthesis:

#6s - 4 = (8*2) + 8*1/4*s)#

#6s - 4 = 16 + 2s#

Now, solve for #s# using the necessary mathematics while keeping the equation balanced:

#6s - 4 + 4 - 2s = 16 + 2s + 4 - 2s#

#6s - 2s - 0 = 16 + 4 + 0#

#(6 - 2)s = 20#

#4s = 20#

#(4s)/4 = 20/4#

#(4/4)s = 5#

#1s = 5#

#s = 5#

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Answer 2

Kennedy Adams

To solve the equation 6s - 4 = 8(2 + 1/4s), first distribute the 8: 6s - 4 = 16 + 2s Then, isolate the variable by subtracting 2s from both sides: 4s - 4 = 16 Add 4 to both sides: 4s = 20 Finally, divide both sides by 4: s = 5

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.