How do you solve #6n=4n+3#?

Answer 1

n = 1.5

Subtract 4n from both sides of the equation, so you are left with 2n = 3 now divide both sides of the equation by 2 and you obtain n = 3/2 (or 1.5) In this type of problem the overall strategy is to isolate the Unknown (n in this case) on one side of the equation. The tactic is to perform the same operations on both sides of the equation ( subtracting 4n, dividing by 2) so as to maintain the equality.

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Answer 2

With practise you will start to use the shortcuts and become much faster at solving this type of question.

#n=3/2#

#color(blue)("Method")#
The trick is to manipulate the equation so that you end up with just one #n# and for it to be on one side of the #=# and everything else on the other side.

The shortcuts people show you are just methods of jumping steps of the first principle method.

#color(Red)("I am using First Principles to move something to the other side of the =")#
#color(purple)("For add or subtract turn it into 0. Anything + 0 does not change.")#
#color(purple)("For multiply or divide turn it into 1. Anything "xx1" does not change.")# '~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Solving your question")#
#color(white)(.)#
Given:#" "color(brown)(6n=4n+3)larr" "4n" is on the right"#
To move the #4n# to the left of = Subtract #color(blue)(4n)# from both sides
#color(brown)(6ncolor(blue)(-4n)=4ncolor(blue)(-4n)+3)#
#color(brown)(6ncolor(blue)(-4n)=color(blue)(0)+3) larr" it is now on the left"#
#=>color(brown)(2n=3)# '............................................................................................................ To move the 2 from #2n# to the right Divide both sides by #color(blue)(2)#
#color(brown)(2/(color(blue)(2))xxn=3/(color(blue)(2))#
#color(brown)(color(blue)(1xx)n=3/(color(blue)(2)) larr" now it is on the right"#
#" "color(red)(n=3/2)#
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Answer 3

To solve the equation 6n = 4n + 3, you need to isolate the variable n. Subtract 4n from both sides of the equation to get 2n = 3. Then, divide both sides by 2 to solve for n. This gives you n = 3/2 or n = 1.5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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