How do you solve #6k+3(k+2)=5k+12#?
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To solve the equation 6k + 3(k + 2) = 5k + 12, first distribute the 3 inside the parentheses: 6k + 3k + 6 = 5k + 12. Then, combine like terms: 9k + 6 = 5k + 12. Next, move the 5k term to the left side by subtracting 5k from both sides: 9k - 5k + 6 = 12. Simplify: 4k + 6 = 12. Now, subtract 6 from both sides: 4k = 6. Finally, divide both sides by 4 to isolate k: k = 6/4 or k = 3/2.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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