How do you solve #6e^(9x)=1548#?

Answer 1

I found #x=0.617#

We can write it as: #e^(9x)=1548/6# #e^(9x)=258# let us take the natural log of both sides: #ln(e^(9x))=ln(258)# #ln# and #e# eliminate each othe and we get: #9x=ln(258)# #x=(ln(258))/9=0.617#

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Answer 2

Chloe Alexander

To solve (6e^{9x} = 1548):

Divide both sides by 6: (e^{9x} = 258).
Take the natural logarithm (ln) of both sides to eliminate the exponential: (ln(e^{9x}) = ln(258)).
Since (ln(e^{9x}) = 9x \cdot ln(e)) and (ln(e) = 1), this simplifies to (9x = ln(258)).
Divide by 9 to solve for (x): (x = \frac{ln(258)}{9}).

So, (x = \frac{ln(258)}{9}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.